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Extra resources for The Art of Multiprocessor Programming, Revised Reprint

Sample text

In the waiting part of the Bakery algorithm (Line 15), a thread repeatedly rereads the labels one after the other in some arbitrary order until it determines that no thread with a raised flag has a lexicographically smaller label/id pair. Since releasing a lock does not reset the label[], it is easy to see that each thread’s labels are strictly increasing. Interestingly, in both the doorway and waiting sections, threads read the labels asynchronously and in an arbitrary order, so that the set of labels seen prior to picking a new one may have never existed in memory at the same time.

While Alice’s flag is raised a) Bob lowers his flag b) Bob waits until Alice’s flag is lowered c) Bob raises his flag 3. As soon as his flag is raised and hers is down, he unleashes his dog. 4. When his dog comes back, he lowers his flag. This protocol rewards further study as a solution to Alice and Bob’s problem. On an intuitive level, it works because of the following flag principle. If Alice and Bob each 1. raises his or her own flag, and then 2. looks at the other’s flag, 8 Chapter 1 Introduction then at least one will see the other’s flag raised (clearly, the last one to look will see the other’s flag raised) and will not let his or her pet enter the yard.

It must be executing the while statement, waiting until either flag[B] becomes false or victim is set to B. What is B doing while A fails to make progress? Perhaps B is repeatedly entering and leaving its critical section. If so, however, then B sets victim to B as soon as it reenters the critical section. Once victim is set to B, it does not change, and A must eventually return from the lock() method, a contradiction. So it must be that B is also stuck in its lock() method call, waiting until either flag[A] becomes false or victim is set to A.

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